19+3x=-8(x-4)-2x

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Solution for 19+3x=-8(x-4)-2x equation: 



19+3x=-8(x-4)-2x

We move all terms to the left:

19+3x-(-8(x-4)-2x)=0



We calculate terms in parentheses: -(-8(x-4)-2x), so:

-8(x-4)-2x

We add all the numbers together, and all the variables

-2x-8(x-4)

We multiply parentheses

-2x-8x+32

We add all the numbers together, and all the variables

-10x+32

Back to the equation:

-(-10x+32)



We get rid of parentheses

3x+10x-32+19=0

We add all the numbers together, and all the variables

13x-13=0

We move all terms containing x to the left, all other terms to the right

13x=13

x=13/13

x=1

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