19+3x=(-x+2)-10

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Solution for 19+3x=(-x+2)-10 equation: 



19+3x=(-x+2)-10

We move all terms to the left:

19+3x-((-x+2)-10)=0

We add all the numbers together, and all the variables

3x-((-1x+2)-10)+19=0



We calculate terms in parentheses: -((-1x+2)-10), so:

(-1x+2)-10

We get rid of parentheses

-1x+2-10

We add all the numbers together, and all the variables

-1x-8

Back to the equation:

-(-1x-8)



We get rid of parentheses

3x+1x+8+19=0

We add all the numbers together, and all the variables

4x+27=0

We move all terms containing x to the left, all other terms to the right

4x=-27

x=-27/4

x=-6+3/4

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