19+(4x-20)=(6x-35)

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Solution for 19+(4x-20)=(6x-35) equation: 



19+(4x-20)=(6x-35)

We move all terms to the left:

19+(4x-20)-((6x-35))=0

We get rid of parentheses

4x-((6x-35))-20+19=0



We calculate terms in parentheses: -((6x-35)), so:

(6x-35)

We get rid of parentheses

6x-35

Back to the equation:

-(6x-35)



We add all the numbers together, and all the variables

4x-(6x-35)-1=0

We get rid of parentheses

4x-6x+35-1=0

We add all the numbers together, and all the variables

-2x+34=0

We move all terms containing x to the left, all other terms to the right

-2x=-34

x=-34/-2

x=+17

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