19(b+3)=-19

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Solution for 19(b+3)=-19 equation: 



19(b+3)=-19

We move all terms to the left:

19(b+3)-(-19)=0

We add all the numbers together, and all the variables

19(b+3)+19=0

We multiply parentheses

19b+57+19=0

We add all the numbers together, and all the variables

19b+76=0

We move all terms containing b to the left, all other terms to the right

19b=-76

b=-76/19

b=-4

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