19(4x-8)-6x+27=15-12(2x-4)

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Solution for 19(4x-8)-6x+27=15-12(2x-4) equation:



19(4x-8)-6x+27=15-12(2x-4)
We move all terms to the left:
19(4x-8)-6x+27-(15-12(2x-4))=0
We add all the numbers together, and all the variables
-6x+19(4x-8)-(15-12(2x-4))+27=0
We multiply parentheses
-6x+76x-(15-12(2x-4))-152+27=0
We calculate terms in parentheses: -(15-12(2x-4)), so:
15-12(2x-4)
determiningTheFunctionDomain -12(2x-4)+15
We multiply parentheses
-24x+48+15
We add all the numbers together, and all the variables
-24x+63
Back to the equation:
-(-24x+63)
We add all the numbers together, and all the variables
70x-(-24x+63)-125=0
We get rid of parentheses
70x+24x-63-125=0
We add all the numbers together, and all the variables
94x-188=0
We move all terms containing x to the left, all other terms to the right
94x=188
x=188/94
x=2

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