19(3x+1x)=28

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Solution for 19(3x+1x)=28 equation: 



19(3x+1x)=28

We move all terms to the left:

19(3x+1x)-(28)=0

We add all the numbers together, and all the variables

19(+4x)-28=0

We multiply parentheses

76x-28=0

We move all terms containing x to the left, all other terms to the right

76x=28

x=28/76

x=7/19

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