18y-6y=-11(y+2)+y

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Solution for 18y-6y=-11(y+2)+y equation:



18y-6y=-11(y+2)+y
We move all terms to the left:
18y-6y-(-11(y+2)+y)=0
We add all the numbers together, and all the variables
12y-(-11(y+2)+y)=0
We calculate terms in parentheses: -(-11(y+2)+y), so:
-11(y+2)+y
We add all the numbers together, and all the variables
y-11(y+2)
We multiply parentheses
y-11y-22
We add all the numbers together, and all the variables
-10y-22
Back to the equation:
-(-10y-22)
We get rid of parentheses
12y+10y+22=0
We add all the numbers together, and all the variables
22y+22=0
We move all terms containing y to the left, all other terms to the right
22y=-22
y=-22/22
y=-1

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