18y-3(2y-5)=6(3y-9)-9y

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Solution for 18y-3(2y-5)=6(3y-9)-9y equation:



18y-3(2y-5)=6(3y-9)-9y
We move all terms to the left:
18y-3(2y-5)-(6(3y-9)-9y)=0
We multiply parentheses
18y-6y-(6(3y-9)-9y)+15=0
We calculate terms in parentheses: -(6(3y-9)-9y), so:
6(3y-9)-9y
We add all the numbers together, and all the variables
-9y+6(3y-9)
We multiply parentheses
-9y+18y-54
We add all the numbers together, and all the variables
9y-54
Back to the equation:
-(9y-54)
We add all the numbers together, and all the variables
12y-(9y-54)+15=0
We get rid of parentheses
12y-9y+54+15=0
We add all the numbers together, and all the variables
3y+69=0
We move all terms containing y to the left, all other terms to the right
3y=-69
y=-69/3
y=-23

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