18x2-6=0

Solution for 18x2-6=0 equation:

18x^2-6=0

a = 18; b = 0; c = -6;
Δ = b2-4ac
Δ = 02-4·18·(-6)
Δ = 432
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{432}=\sqrt{144*3}=\sqrt{144}*\sqrt{3}=12\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{3}}{2*18}=\frac{0-12\sqrt{3}}{36}
=-\frac{12\sqrt{3}}{36}
=-\frac{\sqrt{3}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{3}}{2*18}=\frac{0+12\sqrt{3}}{36}
=\frac{12\sqrt{3}}{36}
=\frac{\sqrt{3}}{3}
$