18x2+9x-35=0

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Solution for 18x2+9x-35=0 equation:



18x^2+9x-35=0
a = 18; b = 9; c = -35;
Δ = b2-4ac
Δ = 92-4·18·(-35)
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2601}=51$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-51}{2*18}=\frac{-60}{36} =-1+2/3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+51}{2*18}=\frac{42}{36} =1+1/6 $

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