18x2+48x+32=0

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Solution for 18x2+48x+32=0 equation: 



18x^2+48x+32=0

a = 18; b = 48; c = +32;
Δ = b2-4ac
Δ = 482-4·18·32
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-48}{36}=-1+1/3$

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