18n2+15n-33=0

Solution for 18n2+15n-33=0 equation:

18n^2+15n-33=0

a = 18; b = 15; c = -33;
Δ = b2-4ac
Δ = 152-4·18·(-33)
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2601}=51$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-51}{2*18}=\frac{-66}{36}
=-1+5/6
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+51}{2*18}=\frac{36}{36}
=1
$