18h+3h(-4h+2)=9

Solution for 18h+3h(-4h+2)=9 equation:

18h+3h(-4h+2)=9

We move all terms to the left:

18h+3h(-4h+2)-(9)=0

We multiply parentheses

-12h^2+18h+6h-9=0

We add all the numbers together, and all the variables

-12h^2+24h-9=0

a = -12; b = 24; c = -9;
Δ = b2-4ac
Δ = 242-4·(-12)·(-9)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-12}{2*-12}=\frac{-36}{-24}
=1+1/2
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+12}{2*-12}=\frac{-12}{-24}
=1/2
$