18=3(p-4)+6

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Solution for 18=3(p-4)+6 equation: 



18=3(p-4)+6

We move all terms to the left:

18-(3(p-4)+6)=0



We calculate terms in parentheses: -(3(p-4)+6), so:

3(p-4)+6

We multiply parentheses

3p-12+6

We add all the numbers together, and all the variables

3p-6

Back to the equation:

-(3p-6)



We get rid of parentheses

-3p+6+18=0

We add all the numbers together, and all the variables

-3p+24=0

We move all terms containing p to the left, all other terms to the right

-3p=-24

p=-24/-3

p=+8

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