18=3(6-2c)+19c

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Solution for 18=3(6-2c)+19c equation:



18=3(6-2c)+19c
We move all terms to the left:
18-(3(6-2c)+19c)=0
We add all the numbers together, and all the variables
-(3(-2c+6)+19c)+18=0
We calculate terms in parentheses: -(3(-2c+6)+19c), so:
3(-2c+6)+19c
We add all the numbers together, and all the variables
19c+3(-2c+6)
We multiply parentheses
19c-6c+18
We add all the numbers together, and all the variables
13c+18
Back to the equation:
-(13c+18)
We get rid of parentheses
-13c-18+18=0
We add all the numbers together, and all the variables
-13c=0
c=0/-13
c=0

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