18=3(2x-3)-3x+6

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Solution for 18=3(2x-3)-3x+6 equation: 



18=3(2x-3)-3x+6

We move all terms to the left:

18-(3(2x-3)-3x+6)=0



We calculate terms in parentheses: -(3(2x-3)-3x+6), so:

3(2x-3)-3x+6

We add all the numbers together, and all the variables

-3x+3(2x-3)+6

We multiply parentheses

-3x+6x-9+6

We add all the numbers together, and all the variables

3x-3

Back to the equation:

-(3x-3)



We get rid of parentheses

-3x+3+18=0

We add all the numbers together, and all the variables

-3x+21=0

We move all terms containing x to the left, all other terms to the right

-3x=-21

x=-21/-3

x=+7

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