18=2/5f*

Solution for 18=2/5f* equation:

18=2/5f*

We move all terms to the left:

18-(2/5f*)=0


Domain of the equation: 5f*)!=0

f!=0/1

f!=0

f∈R


We add all the numbers together, and all the variables

-(+2/5f*)+18=0

We get rid of parentheses

-2/5f*+18=0

We multiply all the terms by the denominator


18*5f*-2=0

Wy multiply elements

90f^2-2=0

a = 90; b = 0; c = -2;
Δ = b2-4ac
Δ = 02-4·90·(-2)
Δ = 720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{720}=\sqrt{144*5}=\sqrt{144}*\sqrt{5}=12\sqrt{5}$
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{5}}{2*90}=\frac{0-12\sqrt{5}}{180}
=-\frac{12\sqrt{5}}{180}
=-\frac{\sqrt{5}}{15}
$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{5}}{2*90}=\frac{0+12\sqrt{5}}{180}
=\frac{12\sqrt{5}}{180}
=\frac{\sqrt{5}}{15}
$