18=2(3k+1)=k

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Solution for 18=2(3k+1)=k equation: 



18=2(3k+1)=k

We move all terms to the left:

18-(2(3k+1))=0



We calculate terms in parentheses: -(2(3k+1)), so:

2(3k+1)

We multiply parentheses

6k+2

Back to the equation:

-(6k+2)



We get rid of parentheses

-6k-2+18=0

We add all the numbers together, and all the variables

-6k+16=0

We move all terms containing k to the left, all other terms to the right

-6k=-16

k=-16/-6

k=2+2/3

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