180=x+(x-12)+(x+30)

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Solution for 180=x+(x-12)+(x+30) equation: 



180=x+(x-12)+(x+30)

We move all terms to the left:

180-(x+(x-12)+(x+30))=0



We calculate terms in parentheses: -(x+(x-12)+(x+30)), so:

x+(x-12)+(x+30)

We get rid of parentheses

x+x+x-12+30

We add all the numbers together, and all the variables

3x+18

Back to the equation:

-(3x+18)



We get rid of parentheses

-3x-18+180=0

We add all the numbers together, and all the variables

-3x+162=0

We move all terms containing x to the left, all other terms to the right

-3x=-162

x=-162/-3

x=+54

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