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180=113+x(x+5)
We move all terms to the left:
180-(113+x(x+5))=0
We calculate terms in parentheses: -(113+x(x+5)), so:We get rid of parentheses
113+x(x+5)
determiningTheFunctionDomain x(x+5)+113
We multiply parentheses
x^2+5x+113
Back to the equation:
-(x^2+5x+113)
-x^2-5x-113+180=0
We add all the numbers together, and all the variables
-1x^2-5x+67=0
a = -1; b = -5; c = +67;
Δ = b2-4ac
Δ = -52-4·(-1)·67
Δ = 293
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{293}}{2*-1}=\frac{5-\sqrt{293}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{293}}{2*-1}=\frac{5+\sqrt{293}}{-2} $
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