180=(x+4)+(3x+-17)+(2x-5)

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Solution for 180=(x+4)+(3x+-17)+(2x-5) equation: 



180=(x+4)+(3x+-17)+(2x-5)

We move all terms to the left:

180-((x+4)+(3x+-17)+(2x-5))=0

We add all the numbers together, and all the variables

-((x+4)+(3x-17)+(2x-5))+180=0



We calculate terms in parentheses: -((x+4)+(3x-17)+(2x-5)), so:

(x+4)+(3x-17)+(2x-5)

We get rid of parentheses

x+3x+2x+4-17-5

We add all the numbers together, and all the variables

6x-18

Back to the equation:

-(6x-18)



We get rid of parentheses

-6x+18+180=0

We add all the numbers together, and all the variables

-6x+198=0

We move all terms containing x to the left, all other terms to the right

-6x=-198

x=-198/-6

x=+33

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