180=(4x)(5x+3)

Solution for 180=(4x)(5x+3) equation:

180=(4x)(5x+3)

We move all terms to the left:

180-((4x)(5x+3))=0


We calculate terms in parentheses: -(4x(5x+3)), so:

4x(5x+3)

We multiply parentheses

20x^2+12x

Back to the equation:

-(20x^2+12x)


We get rid of parentheses

-20x^2-12x+180=0

a = -20; b = -12; c = +180;
Δ = b2-4ac
Δ = -122-4·(-20)·180
Δ = 14544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{14544}=\sqrt{144*101}=\sqrt{144}*\sqrt{101}=12\sqrt{101}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-12\sqrt{101}}{2*-20}=\frac{12-12\sqrt{101}}{-40}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+12\sqrt{101}}{2*-20}=\frac{12+12\sqrt{101}}{-40}
$