180=(3x+5)(2x-25)

Solution for 180=(3x+5)(2x-25) equation:

180=(3x+5)(2x-25)

We move all terms to the left:

180-((3x+5)(2x-25))=0

We multiply parentheses ..

-((+6x^2-75x+10x-125))+180=0


We calculate terms in parentheses: -((+6x^2-75x+10x-125)), so:

(+6x^2-75x+10x-125)

We get rid of parentheses

6x^2-75x+10x-125

We add all the numbers together, and all the variables

6x^2-65x-125

Back to the equation:

-(6x^2-65x-125)


We get rid of parentheses

-6x^2+65x+125+180=0

We add all the numbers together, and all the variables

-6x^2+65x+305=0

a = -6; b = 65; c = +305;
Δ = b2-4ac
Δ = 652-4·(-6)·305
Δ = 11545
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(65)-\sqrt{11545}}{2*-6}=\frac{-65-\sqrt{11545}}{-12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(65)+\sqrt{11545}}{2*-6}=\frac{-65+\sqrt{11545}}{-12}
$