180=(3x+25)2x

Solution for 180=(3x+25)2x equation:

180=(3x+25)2x

We move all terms to the left:

180-((3x+25)2x)=0


We calculate terms in parentheses: -((3x+25)2x), so:

(3x+25)2x

We multiply parentheses

6x^2+50x

Back to the equation:

-(6x^2+50x)


We get rid of parentheses

-6x^2-50x+180=0

a = -6; b = -50; c = +180;
Δ = b2-4ac
Δ = -502-4·(-6)·180
Δ = 6820
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6820}=\sqrt{4*1705}=\sqrt{4}*\sqrt{1705}=2\sqrt{1705}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-2\sqrt{1705}}{2*-6}=\frac{50-2\sqrt{1705}}{-12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+2\sqrt{1705}}{2*-6}=\frac{50+2\sqrt{1705}}{-12}
$