1800(2/5)t=600

Solution for 1800(2/5)t=600 equation:

1800(2/5)t=600

We move all terms to the left:

1800(2/5)t-(600)=0


Domain of the equation: 5)t!=0

t!=0/1

t!=0

t∈R


We add all the numbers together, and all the variables

1800(+2/5)t-600=0

We multiply parentheses

3600t^2-600=0

a = 3600; b = 0; c = -600;
Δ = b2-4ac
Δ = 02-4·3600·(-600)
Δ = 8640000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8640000}=\sqrt{1440000*6}=\sqrt{1440000}*\sqrt{6}=1200\sqrt{6}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-1200\sqrt{6}}{2*3600}=\frac{0-1200\sqrt{6}}{7200}
=-\frac{1200\sqrt{6}}{7200}
=-\frac{\sqrt{6}}{6}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+1200\sqrt{6}}{2*3600}=\frac{0+1200\sqrt{6}}{7200}
=\frac{1200\sqrt{6}}{7200}
=\frac{\sqrt{6}}{6}
$