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180-x=1/2x+12
We move all terms to the left:
180-x-(1/2x+12)=0
Domain of the equation: 2x+12)!=0We add all the numbers together, and all the variables
x∈R
-1x-(1/2x+12)+180=0
We get rid of parentheses
-1x-1/2x-12+180=0
We multiply all the terms by the denominator
-1x*2x-12*2x+180*2x-1=0
Wy multiply elements
-2x^2-24x+360x-1=0
We add all the numbers together, and all the variables
-2x^2+336x-1=0
a = -2; b = 336; c = -1;
Δ = b2-4ac
Δ = 3362-4·(-2)·(-1)
Δ = 112888
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{112888}=\sqrt{4*28222}=\sqrt{4}*\sqrt{28222}=2\sqrt{28222}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(336)-2\sqrt{28222}}{2*-2}=\frac{-336-2\sqrt{28222}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(336)+2\sqrt{28222}}{2*-2}=\frac{-336+2\sqrt{28222}}{-4} $
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