18/56m-12=4m-6

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Solution for 18/56m-12=4m-6 equation:



18/56m-12=4m-6
We move all terms to the left:
18/56m-12-(4m-6)=0
Domain of the equation: 56m!=0
m!=0/56
m!=0
m∈R
We get rid of parentheses
18/56m-4m+6-12=0
We multiply all the terms by the denominator
-4m*56m+6*56m-12*56m+18=0
Wy multiply elements
-224m^2+336m-672m+18=0
We add all the numbers together, and all the variables
-224m^2-336m+18=0
a = -224; b = -336; c = +18;
Δ = b2-4ac
Δ = -3362-4·(-224)·18
Δ = 129024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{129024}=\sqrt{9216*14}=\sqrt{9216}*\sqrt{14}=96\sqrt{14}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-336)-96\sqrt{14}}{2*-224}=\frac{336-96\sqrt{14}}{-448} $
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-336)+96\sqrt{14}}{2*-224}=\frac{336+96\sqrt{14}}{-448} $

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