18-6(4+2x)=3(x+5)+15

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Solution for 18-6(4+2x)=3(x+5)+15 equation: 



18-6(4+2x)=3(x+5)+15

We move all terms to the left:

18-6(4+2x)-(3(x+5)+15)=0

We add all the numbers together, and all the variables

-6(2x+4)-(3(x+5)+15)+18=0

We multiply parentheses

-12x-(3(x+5)+15)-24+18=0



We calculate terms in parentheses: -(3(x+5)+15), so:

3(x+5)+15

We multiply parentheses

3x+15+15

We add all the numbers together, and all the variables

3x+30

Back to the equation:

-(3x+30)



We add all the numbers together, and all the variables

-12x-(3x+30)-6=0

We get rid of parentheses

-12x-3x-30-6=0

We add all the numbers together, and all the variables

-15x-36=0

We move all terms containing x to the left, all other terms to the right

-15x=36

x=36/-15

x=-2+2/5

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