18-3(x-3)=4(4-x)=0

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Solution for 18-3(x-3)=4(4-x)=0 equation: 



18-3(x-3)=4(4-x)=0

We move all terms to the left:

18-3(x-3)-(4(4-x))=0

We add all the numbers together, and all the variables

-3(x-3)-(4(-1x+4))+18=0

We multiply parentheses

-3x-(4(-1x+4))+9+18=0



We calculate terms in parentheses: -(4(-1x+4)), so:

4(-1x+4)

We multiply parentheses

-4x+16

Back to the equation:

-(-4x+16)



We add all the numbers together, and all the variables

-3x-(-4x+16)+27=0

We get rid of parentheses

-3x+4x-16+27=0

We add all the numbers together, and all the variables

x+11=0

We move all terms containing x to the left, all other terms to the right

x=-11

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