18-(4-6y)=12+4y-(10+2y)

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Solution for 18-(4-6y)=12+4y-(10+2y) equation: 



18-(4-6y)=12+4y-(10+2y)

We move all terms to the left:

18-(4-6y)-(12+4y-(10+2y))=0

We add all the numbers together, and all the variables

-(-6y+4)-(12+4y-(2y+10))+18=0

We get rid of parentheses

6y-(12+4y-(2y+10))-4+18=0



We calculate terms in parentheses: -(12+4y-(2y+10)), so:

12+4y-(2y+10)

determiningTheFunctionDomain
4y-(2y+10)+12

We get rid of parentheses

4y-2y-10+12

We add all the numbers together, and all the variables

2y+2

Back to the equation:

-(2y+2)



We add all the numbers together, and all the variables

6y-(2y+2)+14=0

We get rid of parentheses

6y-2y-2+14=0

We add all the numbers together, and all the variables

4y+12=0

We move all terms containing y to the left, all other terms to the right

4y=-12

y=-12/4

y=-3

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