18-(3+x)-2x=4+(x-5)

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Solution for 18-(3+x)-2x=4+(x-5) equation: 



18-(3+x)-2x=4+(x-5)

We move all terms to the left:

18-(3+x)-2x-(4+(x-5))=0

We add all the numbers together, and all the variables

-(x+3)-2x-(4+(x-5))+18=0

We add all the numbers together, and all the variables

-2x-(x+3)-(4+(x-5))+18=0

We get rid of parentheses

-2x-x-(4+(x-5))-3+18=0



We calculate terms in parentheses: -(4+(x-5)), so:

4+(x-5)

determiningTheFunctionDomain
(x-5)+4

We get rid of parentheses

x-5+4

We add all the numbers together, and all the variables

x-1

Back to the equation:

-(x-1)



We add all the numbers together, and all the variables

-3x-(x-1)+15=0

We get rid of parentheses

-3x-x+1+15=0

We add all the numbers together, and all the variables

-4x+16=0

We move all terms containing x to the left, all other terms to the right

-4x=-16

x=-16/-4

x=+4

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