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18+2x=x2-5x
We move all terms to the left:
18+2x-(x2-5x)=0
We add all the numbers together, and all the variables
-(+x^2-5x)+2x+18=0
We get rid of parentheses
-x^2+5x+2x+18=0
We add all the numbers together, and all the variables
-1x^2+7x+18=0
a = -1; b = 7; c = +18;
Δ = b2-4ac
Δ = 72-4·(-1)·18
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-11}{2*-1}=\frac{-18}{-2} =+9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+11}{2*-1}=\frac{4}{-2} =-2 $
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