18+16+(4y-6)=180

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Solution for 18+16+(4y-6)=180 equation: 



18+16+(4y-6)=180

We move all terms to the left:

18+16+(4y-6)-(180)=0

We add all the numbers together, and all the variables

(4y-6)-146=0

We get rid of parentheses

4y-6-146=0

We add all the numbers together, and all the variables

4y-152=0

We move all terms containing y to the left, all other terms to the right

4y=152

y=152/4

y=38

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