18(x+3)=9-5(x+4)-7

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Solution for 18(x+3)=9-5(x+4)-7 equation: 



18(x+3)=9-5(x+4)-7

We move all terms to the left:

18(x+3)-(9-5(x+4)-7)=0

We multiply parentheses

18x-(9-5(x+4)-7)+54=0



We calculate terms in parentheses: -(9-5(x+4)-7), so:

9-5(x+4)-7

determiningTheFunctionDomain
-5(x+4)+9-7

We add all the numbers together, and all the variables

-5(x+4)+2

We multiply parentheses

-5x-20+2

We add all the numbers together, and all the variables

-5x-18

Back to the equation:

-(-5x-18)



We get rid of parentheses

18x+5x+18+54=0

We add all the numbers together, and all the variables

23x+72=0

We move all terms containing x to the left, all other terms to the right

23x=-72

x=-72/23

x=-3+3/23

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