18(x+1)=6(3x-4)+42

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Solution for 18(x+1)=6(3x-4)+42 equation:


Simplifying
18(x + 1) = 6(3x + -4) + 42

Reorder the terms:
18(1 + x) = 6(3x + -4) + 42
(1 * 18 + x * 18) = 6(3x + -4) + 42
(18 + 18x) = 6(3x + -4) + 42

Reorder the terms:
18 + 18x = 6(-4 + 3x) + 42
18 + 18x = (-4 * 6 + 3x * 6) + 42
18 + 18x = (-24 + 18x) + 42

Reorder the terms:
18 + 18x = -24 + 42 + 18x

Combine like terms: -24 + 42 = 18
18 + 18x = 18 + 18x

Add '-18' to each side of the equation.
18 + -18 + 18x = 18 + -18 + 18x

Combine like terms: 18 + -18 = 0
0 + 18x = 18 + -18 + 18x
18x = 18 + -18 + 18x

Combine like terms: 18 + -18 = 0
18x = 0 + 18x
18x = 18x

Add '-18x' to each side of the equation.
18x + -18x = 18x + -18x

Combine like terms: 18x + -18x = 0
0 = 18x + -18x

Combine like terms: 18x + -18x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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