18(t+1)=5(t-10)+55

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Solution for 18(t+1)=5(t-10)+55 equation: 



18(t+1)=5(t-10)+55

We move all terms to the left:

18(t+1)-(5(t-10)+55)=0

We multiply parentheses

18t-(5(t-10)+55)+18=0



We calculate terms in parentheses: -(5(t-10)+55), so:

5(t-10)+55

We multiply parentheses

5t-50+55

We add all the numbers together, and all the variables

5t+5

Back to the equation:

-(5t+5)



We get rid of parentheses

18t-5t-5+18=0

We add all the numbers together, and all the variables

13t+13=0

We move all terms containing t to the left, all other terms to the right

13t=-13

t=-13/13

t=-1

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