18(c-9)=6(2c-12)-4c

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Solution for 18(c-9)=6(2c-12)-4c equation:



18(c-9)=6(2c-12)-4c
We move all terms to the left:
18(c-9)-(6(2c-12)-4c)=0
We multiply parentheses
18c-(6(2c-12)-4c)-162=0
We calculate terms in parentheses: -(6(2c-12)-4c), so:
6(2c-12)-4c
We add all the numbers together, and all the variables
-4c+6(2c-12)
We multiply parentheses
-4c+12c-72
We add all the numbers together, and all the variables
8c-72
Back to the equation:
-(8c-72)
We get rid of parentheses
18c-8c+72-162=0
We add all the numbers together, and all the variables
10c-90=0
We move all terms containing c to the left, all other terms to the right
10c=90
c=90/10
c=9

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