18(3z-2)-10=4(10z-11)+10z-2

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Solution for 18(3z-2)-10=4(10z-11)+10z-2 equation: 



18(3z-2)-10=4(10z-11)+10z-2

We move all terms to the left:

18(3z-2)-10-(4(10z-11)+10z-2)=0

We multiply parentheses

54z-(4(10z-11)+10z-2)-36-10=0



We calculate terms in parentheses: -(4(10z-11)+10z-2), so:

4(10z-11)+10z-2

We add all the numbers together, and all the variables

10z+4(10z-11)-2

We multiply parentheses

10z+40z-44-2

We add all the numbers together, and all the variables

50z-46

Back to the equation:

-(50z-46)



We add all the numbers together, and all the variables

54z-(50z-46)-46=0

We get rid of parentheses

54z-50z+46-46=0

We add all the numbers together, and all the variables

4z=0

z=0/4

z=0

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