18(2x-1)=6(x+2)3x

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Solution for 18(2x-1)=6(x+2)3x equation: 



18(2x-1)=6(x+2)3x

We move all terms to the left:

18(2x-1)-(6(x+2)3x)=0

We multiply parentheses

36x-(6(x+2)3x)-18=0



We calculate terms in parentheses: -(6(x+2)3x), so:

6(x+2)3x

We multiply parentheses

18x^2+36x

Back to the equation:

-(18x^2+36x)



We get rid of parentheses

-18x^2+36x-36x-18=0

We add all the numbers together, and all the variables

-18x^2-18=0

a = -18; b = 0; c = -18;
Δ = b2-4ac
Δ = 02-4·(-18)·(-18)
Δ = -1296
Delta is less than zero, so there is no solution for the equation

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