18(2a-3)(3a+2)=0

Solution for 18(2a-3)(3a+2)=0 equation:

18(2a-3)(3a+2)=0

We multiply parentheses ..

18(+6a^2+4a-9a-6)=0

We multiply parentheses

108a^2+72a-162a-108=0

We add all the numbers together, and all the variables

108a^2-90a-108=0

a = 108; b = -90; c = -108;
Δ = b2-4ac
Δ = -902-4·108·(-108)
Δ = 54756
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{54756}=234$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-90)-234}{2*108}=\frac{-144}{216}
=-2/3
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-90)+234}{2*108}=\frac{324}{216}
=1+1/2
$