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17x^2=14
We move all terms to the left:
17x^2-(14)=0
a = 17; b = 0; c = -14;
Δ = b2-4ac
Δ = 02-4·17·(-14)
Δ = 952
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{952}=\sqrt{4*238}=\sqrt{4}*\sqrt{238}=2\sqrt{238}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{238}}{2*17}=\frac{0-2\sqrt{238}}{34} =-\frac{2\sqrt{238}}{34} =-\frac{\sqrt{238}}{17} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{238}}{2*17}=\frac{0+2\sqrt{238}}{34} =\frac{2\sqrt{238}}{34} =\frac{\sqrt{238}}{17} $
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