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17x^2-33x+10=0
a = 17; b = -33; c = +10;
Δ = b2-4ac
Δ = -332-4·17·10
Δ = 409
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-\sqrt{409}}{2*17}=\frac{33-\sqrt{409}}{34} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+\sqrt{409}}{2*17}=\frac{33+\sqrt{409}}{34} $
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