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17x^2+48x-9=0
a = 17; b = 48; c = -9;
Δ = b2-4ac
Δ = 482-4·17·(-9)
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2916}=54$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-54}{2*17}=\frac{-102}{34} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+54}{2*17}=\frac{6}{34} =3/17 $
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