17x2+16x-6=0

Solution for 17x2+16x-6=0 equation:

17x^2+16x-6=0

a = 17; b = 16; c = -6;
Δ = b2-4ac
Δ = 162-4·17·(-6)
Δ = 664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{664}=\sqrt{4*166}=\sqrt{4}*\sqrt{166}=2\sqrt{166}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-2\sqrt{166}}{2*17}=\frac{-16-2\sqrt{166}}{34}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+2\sqrt{166}}{2*17}=\frac{-16+2\sqrt{166}}{34}
$