17x+15(x+1)=32(x+1)-17

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Solution for 17x+15(x+1)=32(x+1)-17 equation: 


Simplifying
17x + 15(x + 1) = 32(x + 1) + -17

Reorder the terms:
17x + 15(1 + x) = 32(x + 1) + -17
17x + (1 * 15 + x * 15) = 32(x + 1) + -17
17x + (15 + 15x) = 32(x + 1) + -17

Reorder the terms:
15 + 17x + 15x = 32(x + 1) + -17

Combine like terms: 17x + 15x = 32x
15 + 32x = 32(x + 1) + -17

Reorder the terms:
15 + 32x = 32(1 + x) + -17
15 + 32x = (1 * 32 + x * 32) + -17
15 + 32x = (32 + 32x) + -17

Reorder the terms:
15 + 32x = 32 + -17 + 32x

Combine like terms: 32 + -17 = 15
15 + 32x = 15 + 32x

Add '-15' to each side of the equation.
15 + -15 + 32x = 15 + -15 + 32x

Combine like terms: 15 + -15 = 0
0 + 32x = 15 + -15 + 32x
32x = 15 + -15 + 32x

Combine like terms: 15 + -15 = 0
32x = 0 + 32x
32x = 32x

Add '-32x' to each side of the equation.
32x + -32x = 32x + -32x

Combine like terms: 32x + -32x = 0
0 = 32x + -32x

Combine like terms: 32x + -32x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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