17x(1x-1)=17

Solution for 17x(1x-1)=17 equation:

17x(1x-1)=17

We move all terms to the left:

17x(1x-1)-(17)=0

We add all the numbers together, and all the variables

17x(x-1)-17=0

We multiply parentheses

17x^2-17x-17=0

a = 17; b = -17; c = -17;
Δ = b2-4ac
Δ = -172-4·17·(-17)
Δ = 1445
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1445}=\sqrt{289*5}=\sqrt{289}*\sqrt{5}=17\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-17\sqrt{5}}{2*17}=\frac{17-17\sqrt{5}}{34}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+17\sqrt{5}}{2*17}=\frac{17+17\sqrt{5}}{34}
$