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176=x(x+5)
We move all terms to the left:
176-(x(x+5))=0
We calculate terms in parentheses: -(x(x+5)), so:We get rid of parentheses
x(x+5)
We multiply parentheses
x^2+5x
Back to the equation:
-(x^2+5x)
-x^2-5x+176=0
We add all the numbers together, and all the variables
-1x^2-5x+176=0
a = -1; b = -5; c = +176;
Δ = b2-4ac
Δ = -52-4·(-1)·176
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-27}{2*-1}=\frac{-22}{-2} =+11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+27}{2*-1}=\frac{32}{-2} =-16 $
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