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170=x(2x-4)
We move all terms to the left:
170-(x(2x-4))=0
We calculate terms in parentheses: -(x(2x-4)), so:We get rid of parentheses
x(2x-4)
We multiply parentheses
2x^2-4x
Back to the equation:
-(2x^2-4x)
-2x^2+4x+170=0
a = -2; b = 4; c = +170;
Δ = b2-4ac
Δ = 42-4·(-2)·170
Δ = 1376
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1376}=\sqrt{16*86}=\sqrt{16}*\sqrt{86}=4\sqrt{86}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{86}}{2*-2}=\frac{-4-4\sqrt{86}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{86}}{2*-2}=\frac{-4+4\sqrt{86}}{-4} $
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