17-9c=-3(c+3)=2

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Solution for 17-9c=-3(c+3)=2 equation: 



17-9c=-3(c+3)=2

We move all terms to the left:

17-9c-(-3(c+3))=0



We calculate terms in parentheses: -(-3(c+3)), so:

-3(c+3)

We multiply parentheses

-3c-9

Back to the equation:

-(-3c-9)



We get rid of parentheses

-9c+3c+9+17=0

We add all the numbers together, and all the variables

-6c+26=0

We move all terms containing c to the left, all other terms to the right

-6c=-26

c=-26/-6

c=4+1/3

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