17+3(z-2)-11z=-7(z+12)+14

Solution for 17+3(z-2)-11z=-7(z+12)+14 equation:

17+3(z-2)-11z=-7(z+12)+14

We move all terms to the left:

17+3(z-2)-11z-(-7(z+12)+14)=0

We add all the numbers together, and all the variables

-11z+3(z-2)-(-7(z+12)+14)+17=0

We multiply parentheses

-11z+3z-(-7(z+12)+14)-6+17=0


We calculate terms in parentheses: -(-7(z+12)+14), so:

-7(z+12)+14

We multiply parentheses

-7z-84+14

We add all the numbers together, and all the variables

-7z-70

Back to the equation:

-(-7z-70)


We add all the numbers together, and all the variables

-8z-(-7z-70)+11=0

We get rid of parentheses

-8z+7z+70+11=0

We add all the numbers together, and all the variables

-1z+81=0

We move all terms containing z to the left, all other terms to the right

-z=-81

z=-81/-1

z=+81